bash – Script arguments (Addendum)

As I think that is easier delete than write, I did a script to start scripts with the while loop for getopts already written. Then, if I don’t need to use arguments I just have to delete the block.

I called it mkscript.sh and I saved it in my /bin folder.

#!/bin/bash

nom=$1

echo "#!/bin/bash" > $nom
echo "" >> $nom

echo "# Default values
#variable_a=default_a
#variable_b=default_b"

echo "# uncomment to argument
#while getopts a:b: option
#do
#case \${option}
#in
#a) variable_a=\${OPTARG};;
#b) variable_b=\${OPTARG};;
#esac
#done" >> $nom

chmod 751 $nom

vim $nom

The way to use it is:

mkscript.sh name_of_the_new_script

Actually,

nom=$1

is another example of how to read arguments in bash. In this way you have to pass the arguments in order after the name of the script. Then $1 correspond to the first argument, $2 the second argument, ${10} the tenth argument, etc.

The last two commands make the script executable (with chmod; we can change privileges later) and open it in a text editor (vim).

chmod 751 $nom

vim $nom

When I run the script the result is another script already open to edit, like that:

#!/bin/bash

# Default values
#variable_a=default_a
#variable_b=default_b
# Uncomment to argument
#while getopts a:b: option
#do
#case ${option}
#in
#a) variable_a=${OPTARG};;
#b) variable_b=${OPTARG};;
#esac
#done

I only have to change or to add variables and, of course, write the rest of the script.

man chmod

man vim

bash script